p-hat Calculator (Sample Proportion)
Sample proportion p̂ = x/n with its standard error, margin of error and Wald and Wilson confidence intervals.
p̂ = x ÷ n. With 45 successes in 100 trials, p̂ = 0.45, SE = √(0.45 × 0.55 ÷ 100) = 0.0497, and the 95% confidence interval is 0.45 ± 1.96 × 0.0497 = 0.353 to 0.548.
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How to use it
- Enter the number of successes x and the sample size n.
- Choose a confidence level (95% is usual).
- Read p̂, the standard error and the confidence intervals.
What you enter
- Successes x
- Sample size n
- Confidence level
What you get
- p̂ and q̂
- Standard error
- Margin of error
- Wald and Wilson intervals
Formula
p̂ = x/n | SE = √(p̂ q̂ / n) | CI = p̂ ± z* × SE
Worked example: survey
Input: 45 of 100 respondents agree, 95% confidence
Result: p̂ = 0.45; 95% CI 0.353 to 0.548
The true share could plausibly be anywhere from about 35% to 55%.
Questions
How do you find p-hat?
Divide the number of successes (people who said yes, defective items) by the total sample size: p̂ = x ÷ n.
What is the standard error of p-hat?
SE = √(p̂(1 − p̂) ÷ n). It shrinks as the sample grows.
What is the success-failure condition?
The normal approximation is reasonable when n·p̂ and n·(1 − p̂) are both at least 10.
Should I use the Wald or Wilson interval?
Wald (p̂ ± z·SE) is the textbook formula. Wilson is more accurate for small samples or proportions near 0 or 1, and is recommended by most statisticians.
References
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All free tools · By Dr. Zubair Khalid, DVM, MS, PhD.