Grain Bin Calculator (Bushels and Tons)

Bushels and tons of corn, soybeans, wheat or other grain in a round bin, with a level or peaked top.

Bushels = π × r² × depth ÷ 1.2445 (cu ft per bushel), plus a cone of π × r² × peak height ÷ 3 if peaked. A 30 ft bin with 20 ft of corn holds 14,137 cu ft ÷ 1.2445 = 11,360 bu levelled, or about 12,560 bu with a full peak.

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How to use it

  1. Enter the bin diameter and the depth of the level part of the grain.
  2. Choose a levelled top, a full peak, or a measured peak height.
  3. Pick the grain and read bushels, tons and value.

What you enter

What you get

Formula

V = πr²h + πr²h_peak/3 | bu = V / 1.2445 | tons = bu × test weight / 2,000

Worked example

Input: 30 ft bin, 20 ft corn, full peak

Result: About 12,565 bu (352 tons)

The peak alone holds about 1,200 bushels.

Questions

How many bushels are in a grain bin?

Multiply 3.1416 × radius² × grain depth in feet to get cubic feet, then multiply by 0.8036 (or divide by 1.2445) for bushels.

How do I account for the peak?

A peaked top is a cone: π × r² × peak height ÷ 3. A full peak at corn's 23° angle of repose in a 30 ft bin rises about 6.4 ft and adds roughly 1,200 bushels.

How many pounds are in a bushel?

Standard test weights: shelled corn and sorghum 56 lb, soybeans and wheat 60 lb, barley 48 lb, oats 32 lb.

Why is my measured inventory different?

Grain compacts under its own weight in tall bins (several percent), and moisture and fines change bulk density.

Limitations

References

Related reading

More Farm Planning

All free tools · By Dr. Zubair Khalid, DVM, MS, PhD.